document.write( "Question 941934: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36.
\n" ); document.write( "Find the slope of L. Decimal approximations will be marked incorrect.
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\n" ); document.write( "Answer: 3/2\r
\n" ); document.write( "\n" ); document.write( "This is what I'm having trouble with:
\n" ); document.write( "Write an equation for L in terms of the variables x and y. Decimal approximations will be marked incorrect.\r
\n" ); document.write( "\n" ); document.write( "I'm not sure what it wants? I tried using the point-slope form as y=(3/2)(x-6)+9, but it said that was incorrect.
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Algebra.Com's Answer #574187 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the line passing through the point (\"6\", \"9\") and the \"center\" (\"h\",\"k\") of the circle \"%28x+-4%29%5E2+%2B+%28y+-6%29%5E2+=+36\"\r
\n" ); document.write( "\n" ); document.write( "since \"%28x+-4%29%5E2+%2B+%28y+-6%29%5E2+=+36\" we know that \"h=4\" and \"k=6\" (recall the circle formula \"%28x+-h%29%5E2+%2B+%28y+-k%29%5E2+=+r%5E2\" )\r
\n" ); document.write( "\n" ); document.write( "so, we have two points the point (\"6\", \"9\") and the point (\"4\", \"6\") \r
\n" ); document.write( "\n" ); document.write( "now find equation of a line passing through these two points:\r
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (6, 9) and (x2, y2) = (4, 6).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-9%29%2F%284-6%29+=+1.5\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"1.5%2A6+%2Bb+=+0\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=9-1.5%2A6+=+0\".
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\n" ); document.write( " y=(1.5)x + (0)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "since equation is \"y=1.5%2Ax\" which is \"y=%283%2F2%29x\"; so, the slope is \"3%2F2\"
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