document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941907>Question 941907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Marion is 5 years younger than Susan. In 10 years Susan will be 3 times as old as Marion was 3 years ago. Find their present ages. The answer is Susan is 17 and Marion is 12. I just need the  solution to this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #574177 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=574177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Susan's age = S Marion's age=M=S-5<BR>\n" );
document.write( "S+10=3(M-3) Substitute above equation for M<BR>\n" );
document.write( "S+10=3((S-5)-3)<BR>\n" );
document.write( "S+10=3(S-8)<BR>\n" );
document.write( "S+10=3S-24 Subtract S from each side<BR>\n" );
document.write( "S+10-S=3S-24-S<BR>\n" );
document.write( "10=2S-24 Add 24 to each side<BR>\n" );
document.write( "10+24=2S-24+24<BR>\n" );
document.write( "34=2S divide each side by 2<BR>\n" );
document.write( "17=S ANSWER 1 Susan is 17 years<BR>\n" );
document.write( "M=S-5=17-5=12 years ANSWER 2 Marion is 12 years<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "In 10 years, Susan will be 3 times as old as Marion was 3 years ago<BR>\n" );
document.write( "In 10 years, Susan will be 27. 3Years ago Marion was 9<BR>\n" );
document.write( "3*9=27<BR>\n" );
document.write( "27=27<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );