document.write( "Question 941871: Find an equation of the circle with endpoints of a diameter are
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Algebra.Com's Answer #574157 by MathLover1(20850)\"\" \"About 
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Find an equation of the circle with endpoints of a diameter are
\n" ); document.write( "P(\"-1\", \"3\") and QP(\"5\", \"-7\") \r
\n" ); document.write( "\n" ); document.write( "an equation of the circle is \"%28x+-h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2\"; so, we need the coordinates of the center (\"h+\",\"k\") and the radius \"r\"\r
\n" ); document.write( "\n" ); document.write( "First find the coordinates of the center : (\"h+\",\"k\")\r
\n" ); document.write( "\n" ); document.write( "=>\"+x=h+=+%28x1%2Bx2%29%2F2+=+%28-1%2B5%29+%2F2+=+4%2F2=2\"\r
\n" ); document.write( "\n" ); document.write( "=>\"+y+=k=+%28y1%2By2%29%2F2+=+%283-7%29+%2F2+=+-4%2F2=-2\"\r
\n" ); document.write( "\n" ); document.write( "so, C (\"2\",\"-2\") is the center \r
\n" ); document.write( "\n" ); document.write( "now find the radius ( u can find its length by taking the distance between one endpoint and C )\r
\n" ); document.write( "\n" ); document.write( "take (\"2\",\"-2\") and P(\"-1\", \"3\") \r
\n" ); document.write( "\n" ); document.write( "=> \"r+=+sqrt+%28+%282-1%29%5E2+%2B+%28-2-3%29%5E2+%29+\"
\n" ); document.write( "= >\"r+=sqrt+%281%2B25%29+\"\r
\n" ); document.write( "\n" ); document.write( "= >\"r+=sqrt+%2826%29+\"\r
\n" ); document.write( "\n" ); document.write( "= >\"r+=5.83\"\r
\n" ); document.write( "\n" ); document.write( "hence the equation is :\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+2%29%5E2+%2B+%28y%2B2%29%5E2+=+26+\"\r
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