document.write( "Question 941794: A full bathtub is empty at an average rate of 10 minutes. It will fill up to full at an average rate of 8 minutes if the plug is in. How long will it take to fill up to full if the plug is removed and the tap is turned on?\r
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Algebra.Com's Answer #574133 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Rate of emptying:
\n" ); document.write( "( 1 tub ) / ( 10 min )
\n" ); document.write( "Rate of filling with plug in:
\n" ); document.write( "( 1 tub ) / ( 8 min )
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\n" ); document.write( "What you have to realize at this point is
\n" ); document.write( "that the rate of filling is greater than the
\n" ); document.write( "rate of emptying, so if you pull the plug
\n" ); document.write( "out, the tub will EVENTUALLY fill up.
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\n" ); document.write( "Let \"+t+\" = the time in minutes for the tub
\n" ); document.write( "to fill if the tap is on and the plug is removed
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\n" ); document.write( "Add the rate of filling
\n" ); document.write( "Subtract the rate of emptying
\n" ); document.write( "Make that equal to:
\n" ); document.write( "( 1 tub filled ) / ( t min ) = \"+1%2Ft+\"
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\n" ); document.write( "\"+1%2F8+-+1%2F10+=+1%2Ft+\"
\n" ); document.write( "Multiply both sides by \"+40t+\"
\n" ); document.write( "\"+5t+-+4t+=+40+\"
\n" ); document.write( "\"+t+=+40+\"
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\n" ); document.write( "In 40 min the tub will fill if the tap is
\n" ); document.write( "on and the plug is removed
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\n" ); document.write( "check:
\n" ); document.write( "\"+1%2F8+-+1%2F10+=+1%2F40+\"
\n" ); document.write( "\"+5%2F40+-+4%2F40+=+1%2F40+\"
\n" ); document.write( "\"+1%2F40+=+1%2F40+\"
\n" ); document.write( "OK
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