document.write( "Question 941794: A full bathtub is empty at an average rate of 10 minutes. It will fill up to full at an average rate of 8 minutes if the plug is in. How long will it take to fill up to full if the plug is removed and the tap is turned on?\r
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document.write( "Please provide solution steps. \n" );
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Algebra.Com's Answer #574133 by josmiceli(19441) You can put this solution on YOUR website! Rate of emptying: \n" ); document.write( "( 1 tub ) / ( 10 min ) \n" ); document.write( "Rate of filling with plug in: \n" ); document.write( "( 1 tub ) / ( 8 min ) \n" ); document.write( "-------------------- \n" ); document.write( "What you have to realize at this point is \n" ); document.write( "that the rate of filling is greater than the \n" ); document.write( "rate of emptying, so if you pull the plug \n" ); document.write( "out, the tub will EVENTUALLY fill up. \n" ); document.write( "-------------------- \n" ); document.write( "Let \n" ); document.write( "to fill if the tap is on and the plug is removed \n" ); document.write( "-------------------- \n" ); document.write( "Add the rate of filling \n" ); document.write( "Subtract the rate of emptying \n" ); document.write( "Make that equal to: \n" ); document.write( "( 1 tub filled ) / ( t min ) = \n" ); document.write( "------------------------------- \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------- \n" ); document.write( "In 40 min the tub will fill if the tap is \n" ); document.write( "on and the plug is removed \n" ); document.write( "-------------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |