document.write( "Question 941784: THE SUM OF AN INFINITE GEOMETRIC PROGRESSION IS 15 AND THE SUM OF THE SQUARES OF THESE TERMS IS 45. FIND THE SERIES.
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Algebra.Com's Answer #574132 by srinivas.g(540)\"\" \"About 
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The formula for sum of infinite GP is \"+a%2F%281-r%29\"
\n" ); document.write( " hence \"+a%2F%281-r%29+=15\"..........eq(1)
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\n" ); document.write( "HE SUM OF THE SQUARES OF THESE TERMS IS 45
\n" ); document.write( " hence \"+a%5E2%2F%281-r%5E2%29+=45\" ......eq(2)
\n" ); document.write( " divide eq(1) with eq (2)
\n" ); document.write( " \"+%28+a%2F%281-r%29%29%2F%28%28a%5E2%2F%281-r%5E2%29%29%29+=15%2F45\"
\n" ); document.write( " \"+%28+a%2F%281-r%29%29%2F%28%28a%5E2%2F%281-r%29%281%2Br%29%29%29%29+=15%2F45\"
\n" ); document.write( " \"%281%2F1%29%2F%28a%2F%281%2Br%29+%29=1%2F3\"
\n" ); document.write( " \"%281%2Br%29%2Fa=1%2F3\"
\n" ); document.write( " \"a%2F%281%2Br%29+=3\"
\n" ); document.write( " move (1+r) to the right
\n" ); document.write( " \"+a=+%281%2Br%29%2A3\"
\n" ); document.write( " but from eq(1) \"+a%2F%281-r%29+=15\"
\n" ); document.write( " move (1-r) to the right
\n" ); document.write( " \"+a=+%281-r%29%2A15\"
\n" ); document.write( " from above expressions
\n" ); document.write( " \"%281%2Br%29%2A3++=+%281-r%29%2A15\"
\n" ); document.write( " 3+3*r= 15*1-r*15
\n" ); document.write( " 3+3r =15-15r
\n" ); document.write( " move -15r to the left
\n" ); document.write( " 3+3r+15r =15
\n" ); document.write( " 3+18r =15
\n" ); document.write( " 18r =15-3
\n" ); document.write( " 18r =12
\n" ); document.write( " r = \"+12%2F18\"
\n" ); document.write( " r= \"2%2F3\"
\n" ); document.write( " but a = (1+r)*3
\n" ); document.write( " = \"%281%2B%282%2F3%29%29%2A3\"
\n" ); document.write( " =\"%28%283%2F3%29+%2B%282%2F3%29%29%2A3\"
\n" ); document.write( " = \"+%28%283%2B2%29%2F3+%29%2A3\"
\n" ); document.write( " = 5
\n" ); document.write( "a= 5, r= 2/3
\n" ); document.write( "series = 5, 10/3, 20/9,...
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