document.write( "Question 941743: 4 years ago katie was twice as old as anne was. In 6 years ann will be the same age that katie is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #574112 by macston(5194)\"\" \"About 
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Katie's age=K Anne's age=A
\n" ); document.write( "K-4=2(A-4)
\n" ); document.write( "A+6=K Substitute this in first equation for K
\n" ); document.write( "(A+6)-4=2(A-4)
\n" ); document.write( "A+2=2A-8 add 8 to each side
\n" ); document.write( "A+2+8=2A-8+8
\n" ); document.write( "A+10=2A Subtract A from each side
\n" ); document.write( "A+10-A=2A-A
\n" ); document.write( "10=A ANSWER Anne is 10 years old
\n" ); document.write( "K=A+6=16 ANSWER Katie is 16 years old
\n" ); document.write( "CHECK
\n" ); document.write( "4 years ago Anne was 6 and Katie was 12 (twice as old)
\n" ); document.write( "In 6 years Anne will be 16 (Katie's age now)
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