document.write( "Question 941764: A jogger can bike 30 miles in the same time as he can run 10 miles. If he can bike 10 miles an hour faster than he can job, how fast can he jog? \n" ); document.write( "
Algebra.Com's Answer #574102 by ankor@dixie-net.com(22740)\"\" \"About 
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A jogger can bike 30 miles in the same time as he can run 10 miles.
\n" ); document.write( " If he can bike 10 miles an hour faster than he can job, how fast can he jog?
\n" ); document.write( ":
\n" ); document.write( "let s = his jogging speed
\n" ); document.write( "then
\n" ); document.write( "(s+10) = his biking speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"30%2F%28%28s%2B10%29%29\" = \"10%2Fs\"
\n" ); document.write( "cross multiply
\n" ); document.write( "30s = 10(s+10)
\n" ); document.write( "30s = 10s + 100
\n" ); document.write( "30s - 10s = 100
\n" ); document.write( "20s = 100
\n" ); document.write( "s = 100/20
\n" ); document.write( "s = 5 mph is his jogging speed
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Confirm this by finding the time of each
\n" ); document.write( "30/15 = 2 hrs running (he runs 10 mph faster than he jogs)
\n" ); document.write( "10/5 = 2 hrs jogging \r
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