document.write( "Question 941651: A purse contains 58 coins consisting of dimes and nickels. If the total amount of these coins amounted to $4.80, how many dimes and nickels are in the purse? \n" ); document.write( "
Algebra.Com's Answer #574054 by Edwin McCravy(20060)\"\" \"About 
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A purse contains 58 coins consisting of dimes and nickels. If the total amount of these coins amounted to $4.80, how many dimes and nickels are in the purse?
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document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of dimes, using \r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 58-x.  \r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "NICKELS      x        $0.05    $0.05x \r\n" );
document.write( "DIMES      58-x       $0.10    $0.10(56-x)\r\n" );
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document.write( "TOTALS      58        -----    $4.80\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "  \"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cnickels%29%29\"\"%22%22%2B%22%22\"\"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cdimes%29%29\"\"%22%22=%22%22\"\"%28matrix%284%2C1%2CTotal%2Cvalue%2Cof%2Ccoins%29%29\"\r\n" );
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document.write( "0.05x + 0.10(58-x) = 4.80\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100\r\n" );
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document.write( "     5x + 10(58-x) = 480\r\n" );
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document.write( "    5x + 580 - 10x = 480\r\n" );
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document.write( "         -5x + 580 = 480\r\n" );
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document.write( "               -5x = -100\r\n" );
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document.write( "                 x = 20 = the number of nickels\r\n" );
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document.write( "The number of dimes is 58-x or 58-20 or 38 dimes.\r\n" );
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document.write( "Checking:  20 nickels is $1.00 and 38 dimes is $3.80\r\n" );
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document.write( "And indeed $1.00+$3.80 = $4.80.\r\n" );
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document.write( "Edwin

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