document.write( "Question 941677: Hi
\n" ); document.write( "box a is 3.45 kg heavier than box b.when 1.2 kg in box a was removed, box a became 4 times as
\n" ); document.write( "heavy as box b.what was the mass of box a in the beginning.\r
\n" ); document.write( "\n" ); document.write( "help! \n" ); document.write( "

Algebra.Com's Answer #574053 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+a+\"$ = mass in kg of box a at beginning
\n" ); document.write( "Let $\"+b+\"$ = mass in kg of box b at beginning
\n" ); document.write( "--------------------
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+a+=+b+%2B+3.45+\"$
\n" ); document.write( "(2) $\"+a+-+1.2+=+4b+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "(1) $\"+a+-+b+=+3.45+\"$
\n" ); document.write( "(2) $\"+a+-+4b+=+1.2+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "Subtract (2) from (1)
\n" ); document.write( "(1) $\"+a+-+b+=+3.45+\"$
\n" ); document.write( "(2) $\"+-a+%2B+4b+=+-1.2+\"$
\n" ); document.write( "----------------------
\n" ); document.write( " $\"+3b+=+2.25+\"$
\n" ); document.write( " $\"+b+=+.75+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+a+-+1.2+=+4%2A.75+\"$
\n" ); document.write( "(2) $\"+a+=+1.2+%2B+3+\"$
\n" ); document.write( "(2) $\"+a+=+4.2+\"$
\n" ); document.write( "Box a was 4.2 kg
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+a+-+b+=+3.45+\"$
\n" ); document.write( "(1) $\"+4.2+-+.75+=+3.45+\"$
\n" ); document.write( "(1) $\"+3.45+=+3.45+\"$ \r
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\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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