document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79879>Question 79879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi i have been trying to do these equations for such a long time and i just cant do it please help me\r<BR>\n" );
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document.write( "Write an equation of the line that is parallel to the given line and passes though the given point.\r<BR>\n" );
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document.write( "10. y= -3x+2 (2,3)         11.   y=1/2x - 5 (-3,-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57403 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lines that are parallel have the same slope (the m in y=mx+b), but have different y-intercepts (the b term)\r<BR>\n" );
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document.write( "when a line goes through a point, it means that the x and y values of the point satisfy (fit) the equation of the line\r<BR>\n" );
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document.write( "y=-3x+b for x=2, y=3 ... 3=-3(2)+b ... 3=-6+b ... b=9 ... y=-3x+9\r<BR>\n" );
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document.write( "y=(1/2)x+b for x=-3, y=-1 ... -1=(1/2)(-3)+b ... -1=-(3/2)+b ... b=1/2 ... y=(1/2)x+(1/2) </SPAN>\n" );
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