document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80015>Question 80015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between (–4, 0) and (–5, –3)\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57402 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the x distance is (5-4)=1<BR>\n" );
document.write( "the y distance is (3-0)=3<BR>\n" );
document.write( "therefore the distance is found by the pythagoreon theorem <BR>\n" );
document.write( "a^2+b^2=c^2 a=x distance, b=y distance & c=hypotenuse <BR>\n" );
document.write( "1^2+3^2=c^2<BR>\n" );
document.write( "1+9=c^2<BR>\n" );
document.write( "c^2=10<BR>\n" );
document.write( "c=sqrt10<BR>\n" );
document.write( "c=3.16 answer for the hypotenuse ofr distance between the given points.\r<BR>\n" );
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