document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941565>Question 941565</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice<BR>\n" );
document.write( "as fast as the third,find the number of hours that will take the two faster men to dig this hole together. ( answer is 70hours - show your solution ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573985 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If it takes 3men 56hours to dig a hole 4mX6mX5m, and <BR>\n" );
document.write( " two of the men work twice as fast as the third,\r<BR>\n" );
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document.write( "let t = time required by the faster man to do the job alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2t = time required by the slower man alone<BR>\n" );
document.write( "let the completed job = 1<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A shared work equation for the three men<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=56%2F%282t%29 ALIGN=MIDDLE  ALT=\"56%2F%282t%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=56%2Ft ALIGN=MIDDLE  ALT=\"56%2Ft\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=56%2Ft ALIGN=MIDDLE  ALT=\"56%2Ft\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1<BR>\n" );
document.write( "multiply equation by 2t, cancel the denominators and you have:<BR>\n" );
document.write( "56 + 2(56) + 2(56) = 2t<BR>\n" );
document.write( "56 + 112 + 112<BR>\n" );
document.write( "280 = 2t<BR>\n" );
document.write( "t = 280/2<BR>\n" );
document.write( "t = 140 hrs alone, the faster guy<BR>\n" );
document.write( ":<BR>\n" );
document.write( " find the number of hours that will take the two faster men to dig this hole together.<BR>\n" );
document.write( "let x = no. hrs the two working together<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F140 ALIGN=MIDDLE  ALT=\"x%2F140\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F140%29 ALIGN=MIDDLE  ALT=\"x%2F140%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1<BR>\n" );
document.write( "multiply by 140<BR>\n" );
document.write( " x + x = 140 <BR>\n" );
document.write( "2x = 140<BR>\n" );
document.write( "x = 70 hrs, the two faster guys working </SPAN>\n" );
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