document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941558>Question 941558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first side of a triangle is twice as long as the second side. The remaining side is 9 m longer than the second side. The perimeter is 53 m. How long is each side?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573975 by </B><A HREF=/tutors/aboutme.mpl?userid=srinivas.g><B>srinivas.g(540)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=srinivas.g><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=srinivas.g><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the length of second side<BR>\n" );
document.write( " first side  =  2x<BR>\n" );
document.write( "  third side  = x+9<BR>\n" );
document.write( " perimeter ( sum of length of all 3 sides) = 53 m<BR>\n" );
document.write( "  x+2x+x+9 = 53<BR>\n" );
document.write( "  4x+9 =53<BR>\n" );
document.write( "   move 9  tot he right<BR>\n" );
document.write( "4x=53-9 <BR>\n" );
document.write( "  4x= 44<BR>\n" );
document.write( "  diivde with 4 on both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4x%2F4+=44%2F4 ALIGN=MIDDLE  ALT=\"+4x%2F4+=44%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " x=11<BR>\n" );
document.write( "length of fist side (x) =11 m<BR>\n" );
document.write( " length of second side(2x) =2*11 =22 m<BR>\n" );
document.write( "length of third side(x+9) =11+9 = 20 m<BR>\n" );
document.write( " Result : lengths all 3 sides as follows  11 m,22 m,20 m<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );