document.write( "Question 941572: Bob's father is 3 times old as Bob. 4 years ago, he was 4 times older. How old is Bob? \n" ); document.write( "
Algebra.Com's Answer #573972 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! let present age of bob be x years \n" ); document.write( " bob's father = 3times bob's age \n" ); document.write( " = 3x \n" ); document.write( "4 years ago, age of bob = x-4 \n" ); document.write( " 4 years ago, age of father = 3x-4 \n" ); document.write( " 4 years afo father's age = 34 times bob's age \n" ); document.write( " 3x-4 =4(x-4) \n" ); document.write( " 3x-4 = 4x-16 \n" ); document.write( " 16+3x-4= 4x \n" ); document.write( " 12 +3x=4x \n" ); document.write( " 12 = 4x-3x \n" ); document.write( " 12 =x \n" ); document.write( "Result: age of bob(x)= 12 years\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |