document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80022>Question 80022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equasion of the line which passes through point (2,1) and is parallel to the line with equasion y=5/2x+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57396 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A PARALLEL LINE NEEDS TO HAVE THE SAME SLOPE. THUS THE SLOPE IS 5/2. NOW SUBSTITUTE (2,1) FOR X & Y IN THE QUADRATIC EQUATION Y=mX+b <BR>\n" );
document.write( "1=5/2*2+b<BR>\n" );
document.write( "1=5+b<BR>\n" );
document.write( "b=1-5<BR>\n" );
document.write( "b=-4 Y INTERCEPT.<BR>\n" );
document.write( "THEREFORE THE EQUATION OF THIS PARALLEL LINE PASSING THRU (2,1) IS<BR>\n" );
document.write( "Y=5/2X-4   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );