document.write( "Question 80036: Mr.Harvey invested a sum of money at 4%.He invested a second sum at 3%.If the annual income from the first investment is equal to the annual income from the second investment,and if the investments total $7000,how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #57395 by stanbon(75887)\"\" \"About 
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Mr.Harvey invested a sum of money at 4%.He invested a second sum at 3%.If the annual income from the first investment is equal to the annual income from the second investment,and if the investments total $7000,how much did he invest at each rate?
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\n" ); document.write( "Let \"x\" be amt invested at 4%; Interest on this is 0.04x dollars
\n" ); document.write( "Then \"7000-x\" is amt invested at 3%; Interest on this is 0.03(7000-x)
\n" ); document.write( "= 210-0.03x dollars
\n" ); document.write( "EQUATION:
\n" ); document.write( "1st interest = 2nd interest
\n" ); document.write( "0.04x=210-0.03x
\n" ); document.write( "0.07x=210
\n" ); document.write( "x=3000 (amount invested at 4%)
\n" ); document.write( "7000-x=4000 (amount invested at 3%)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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