document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941509>Question 941509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if perry goes for a 3 hour trip through town on country roads. If she averages 55mph on country roads and 35 mph through the towns, and if she travels 3 times as far on country roads as she does through towns, what is the total length of her trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573941 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perry goes for a 3 hour trip through town and country roads.<BR>\n" );
document.write( " If she averages 55mph on country roads and 35 mph through the towns, and if she travels 3 times as far on country roads as she does through towns, what is the total length of her trip?<BR>\n" );
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document.write( "Let d = distance traveled in town<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3d = distance traveled on country roads<BR>\n" );
document.write( "and<BR>\n" );
document.write( "4d = total distance traveled<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Write a time equation; time = dist/speed<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Town travel time + country travel time = 3 hrs<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F35 ALIGN=MIDDLE  ALT=\"d%2F35\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283d%29%2F55 ALIGN=MIDDLE  ALT=\"%283d%29%2F55\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 3<BR>\n" );
document.write( "multiply equation by the LCM of 35 & 55, namely 1925<BR>\n" );
document.write( "1925*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F35 ALIGN=MIDDLE  ALT=\"d%2F35\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 1925*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283d%29%2F55 ALIGN=MIDDLE  ALT=\"%283d%29%2F55\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 3(1925)<BR>\n" );
document.write( "Cancel the denominators<BR>\n" );
document.write( "55d + 35(3d) = 5775<BR>\n" );
document.write( "55d + 105d = 5775<BR>\n" );
document.write( "160d = 5775<BR>\n" );
document.write( "d = 5775/160<BR>\n" );
document.write( "d = 36.1 mi in the town<BR>\n" );
document.write( "we know 4d = total distance<BR>\n" );
document.write( "4(36.1) = 144.4 mi the length of the trip<BR>\n" );
document.write( ":<BR>\n" );
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document.write( "Check this by finding the actual times<BR>\n" );
document.write( "36.1/35 = 1.03 hrs<BR>\n" );
document.write( "3(36.1)/55 = 1.97 hrs<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "total travel time: 3 hrs\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );