document.write( "Question 941480: Jim built a rectangular shed with a total floor surface area will be 126 sq.ft if the lenght is 4 feet more than twice it's width what is the width of the dog house. Please help me with this \n" ); document.write( "
Algebra.Com's Answer #573922 by MathTherapy(10555)\"\" \"About 
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Jim built a rectangular shed with a total floor surface area will be 126 sq.ft if the lenght is 4 feet more than twice it's width what is the width of the dog house. Please help me with this
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document.write( "Let width be W
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document.write( "Then length = 2W + 4
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document.write( "Since area is 126 sq feet, we get: W(2W + 4) = 126
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document.write( "\"2W%5E2+%2B+4W+-+126+=+0\"
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document.write( "\"2%28W%5E2+%2B+2W+-+63%29+=+2%280%29\"
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document.write( "\"W%5E2+%2B+2W+-+63+=+0\"
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document.write( "(W - 7)(W + 9) = 0
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document.write( "W, or width = \"highlight_green%287%29\" ft             OR            W = - 9 (ignore) \n" );
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