document.write( "Question 941502: cone p and cone q are shown at the right . the volume of cone p is 840 cubic centimeters. the volume of cone q is one-third the volume of cone p about how many times longer is the diameter of cone p than the diameter of cone q? round to the nearest tenth
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #573911 by srinivas.g(540)\"\" \"About 
You can put this solution on YOUR website!
let r1 be the radius of cone p
\n" ); document.write( "let r2 be the radius of cone q
\n" ); document.write( "volume of cone p = 840 cm^3
\n" ); document.write( "volume of cone q =one third of volume of cone p
\n" ); document.write( " = 840/3
\n" ); document.write( " = 280 cm^3
\n" ); document.write( "Formula : volume of cone V =\"%281%2F3%29%2Api%2Ar%5E2%2Ah\"
\n" ); document.write( " \"+840+=+%281%2F3%29%2Api%2Ar1%5E2%2Ah\"
\n" ); document.write( " multiply with 3 on both sides
\n" ); document.write( " \"+840%2A3+=%281%2F3%29%2A3%2Api%2Ar1%5E2%2Ah\"
\n" ); document.write( "\"2520=+pi%2Ar1%5E2%2Ah\"..............eq(1)\r
\n" ); document.write( "\n" ); document.write( " similarly for cone q
\n" ); document.write( " \"+280+=+%281%2F3%29%2Api%2Ar2%5E2%2Ah\"
\n" ); document.write( " [[[ 280*3 = pi*r2^2*h}}}
\n" ); document.write( " \"840+=pi%2Ar2%5E2%2Ah\"..............eq(2)
\n" ); document.write( " divide eq(1) with eq(2)
\n" ); document.write( "\"+2520%2F840+=%28pi%2Ar1%5E2%2Ah%29%2F%28pi%2Ar2%5E2%2Ah%29\"
\n" ); document.write( " \"+3=+r1%5E2%2Fr2%5E2\"
\n" ); document.write( " \"+%28r1%2Fr2%29%5E2+=+3\"
\n" ); document.write( " \"+r1%2Fr2+=sqrt%283%29\"
\n" ); document.write( " \"r1%2Fr2=1.73\"
\n" ); document.write( " r1= 1.73*r2
\n" ); document.write( "radius of cone p = 1.73 time radius of cone q
\n" ); document.write( " diameter = 2* radius
\n" ); document.write( "the above rule applicable to diameter also
\n" ); document.write( "Result : diameter of cone p =1.73 times the diameter of cone q\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );