document.write( "Question 941323: Show that vector n [2, 4, 6] is perpendicular to every vector on the plane:
\n" ); document.write( "2x + 4y + 6z = 12\r
\n" ); document.write( "\n" ); document.write( "I'd offer what I've tried, but honestly, I have no clue. My textbook doesn't seem to illustrate a similar problem, and I cannot find a similar solution in my notes.\r
\n" ); document.write( "\n" ); document.write( "Please assist! It's greatly appreciated!
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Algebra.Com's Answer #573812 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let \"u\" and \"v\" be two vectors in the plane.
\n" ); document.write( "\"u\"=(\"x%5B1%5D\",\"y%5B1%5D\",\"z%5B1%5D\")
\n" ); document.write( "\"v\"=(\"x%5B2%5D\",\"y%5B2%5D\",\"z%5B2%5D\")
\n" ); document.write( "Since they're in the plane,
\n" ); document.write( "1.\"2x%5B1%5D%2B4y%5B1%5D%2B6z%5B1%5D=12\"
\n" ); document.write( "2.\"2x%5B2%5D%2B4y%5B2%5D%2B6z%5B2%5D=12\"
\n" ); document.write( "If you subtract eq. 1 from eq. 2,
\n" ); document.write( "3.\"2%28x%5B2%5D-x%5B1%5D%29%2B4%28y%5B2%5D-y%5B1%5D%29%2B6%28z%5B2%5D-z%5B1%5D%29=0\"
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\n" ); document.write( "If they are perpendicular to the normal vector, then the dot product of each vector with the normal will be zero.
\n" ); document.write( "\"u%2An=0\"
\n" ); document.write( "(\"x%5B1%5D\",\"y%5B1%5D\",\"z%5B1%5D\")*(\"2\",\"4\",\"6\")=\"0\"
\n" ); document.write( "4.\"2x%5B1%5D%2B4y%5B1%5D%2B6z%5B1%5D=0\"
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\n" ); document.write( "\"v%2An=0\"
\n" ); document.write( "(\"x%5B2%5D\",\"y%5B2%5D\",\"z%5B2%5D\")*(\"2\",\"4\",\"6\")=\"0\"
\n" ); document.write( "5.\"2x%5B2%5D%2B4y%5B2%5D%2B6z%5B2%5D=0\"
\n" ); document.write( "So then if I subtract the two dot products,
\n" ); document.write( "6.\"2%28x%5B2%5D-x%5B1%5D%29%2B4%28y%5B2%5D-y%5B1%5D%29%2B6%28z%5B2%5D-z%5B1%5D%29=0\"
\n" ); document.write( "Comparing eq. 6 to eq. 3, you recognize they are identical.\r
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