document.write( "Question 941345: A cylinder with radius 9 feet and height 9 feet has its radius tripled. How many times greater is the volume of the larger cylinder than the smaller cylinder? \n" ); document.write( "
Algebra.Com's Answer #573799 by srinivas.g(540)\"\" \"About 
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radius (r) = 9 feet
\n" ); document.write( " height (h) = 9 feet
\n" ); document.write( " Formula : Volume (V)= \"+Pi%2Ar%5E2%2Ah\"
\n" ); document.write( " V = \"pi%2A9%5E2%2A9\"
\n" ); document.write( " V =\"+pi%2A729\"
\n" ); document.write( " V= \"729%2Api\"
\n" ); document.write( " now radius becomes triple
\n" ); document.write( " hence r2 = 3*9 = 27
\n" ); document.write( " new volume = \"+Pi%2Ar2%5E2%2Ah\"
\n" ); document.write( " = \"+pi%2A27%5E2%2A9\"
\n" ); document.write( " =\"pi%2A729%2A9\"
\n" ); document.write( " but initial volume = \"+729%2Api\"
\n" ); document.write( " = initial volume x 9
\n" ); document.write( " Result : larger cylinder volume = 9 times the smaller cylinder volume
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