document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941342>Question 941342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the diameter of the circle x^2+y^2-4x+6y=14 which passes through the origin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573791 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-4x%2By%5E2%2B6y=14 ALIGN=MIDDLE  ALT=\"x%5E2-4x%2By%5E2%2B6y=14\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The LINE containing the diameter would contain the circle's center of (2,-3), AND also the origin (0,0).  You could put limitations on the domain for the line to achieve just the diameter segment; but in any case, you can find the line containing those two points.  The equation for the line is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-%283%2F2%29x ALIGN=MIDDLE  ALT=\"y=-%283%2F2%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Find the endpoints of the diameter using the equation of the circle and the equation y=-(3/2)x.  Substitute for y in the circle equation, solve for x, and find the corresponding y value....  you have the endpoints of the diameter. </SPAN>\n" );
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