document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941283>Question 941283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which value of x satisfies cos(3.14/2+x)=-1 ?<BR>\n" );
document.write( "A. (3.14/4)<BR>\n" );
document.write( "B. (3.14/2)<BR>\n" );
document.write( "C. 3.14<BR>\n" );
document.write( "D. 2(3.14) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573767 by </B><A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><B>TimothyLamb(4379)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TimothyLamb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> assume that the angular measures are in radians:<BR>\n" );
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document.write( "assume that 3.14 in the given equation stands for pi:<BR>\n" );
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document.write( "cos( (3.14/2) + x ) = -1<BR>\n" );
document.write( "acos( cos( (3.14/2) + x ) ) = acos( -1 )<BR>\n" );
document.write( "(3.14/2) + x = acos( -1 )<BR>\n" );
document.write( "x = acos( -1 ) - (3.14/2)<BR>\n" );
document.write( "x = pi - pi/2<BR>\n" );
document.write( "x = 2pi/2 - pi/2<BR>\n" );
document.write( "x = pi/2<BR>\n" );
document.write( "x = 3.14/2<BR>\n" );
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document.write( "answer:<BR>\n" );
document.write( "B. (3.14/2)<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );