document.write( "Question 941248: george can ride his bike to work in 3/4 hour. if he takes his car to work, the trip takes 1/6 hour. if he drives his car an average of 14 miles per hour faster than he rides his bike, determine the distance he travels to work. \n" ); document.write( "
Algebra.Com's Answer #573748 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = distance in miles to work
\n" ); document.write( "Let \"+s+\" = his speed on his bike in mi/hr
\n" ); document.write( "--------------------------------------
\n" ); document.write( "Equation for riding bike:
\n" ); document.write( "(1) \"+d+=+s%2A%283%2F4%29+\"
\n" ); document.write( "Equation for driving car:
\n" ); document.write( "(2) \"+d+=+%28+s%2B14+%29%2A%281%2F6%29+\"
\n" ); document.write( "------------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+s%2A%283%2F4%29+=+%28+s%2B14+%29%2A%281%2F6%29+\"
\n" ); document.write( "Multiply both sides by \"+12+\"
\n" ); document.write( "\"+3%2As%2A3+=+2%2A%28+s%2B14+%29+\"
\n" ); document.write( "\"+9s+=+2s+%2B+28+\"
\n" ); document.write( "\"+7s+=+28+\"
\n" ); document.write( "\"+s+=+4+\"
\n" ); document.write( "\"+s+%2B+14+=+18+\"
\n" ); document.write( "-----------------
\n" ); document.write( "(1) \"+d+=+4%2A%283%2F4%29+\"
\n" ); document.write( "(1) \"+d+=+3+\"
\n" ); document.write( "The distance to work is 3 mi
\n" ); document.write( "--------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+18%2A%281%2F6%29+\"
\n" ); document.write( "(2) \"+d+=+3+\" mi
\n" ); document.write( "OK\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );