document.write( "Question 941231: Khang and Hector live 88 miles apart in southeastern Missouri. They
\n" ); document.write( "decide to bicycle towards each other and meet somewhere in between.
\n" ); document.write( "Hectorʹs rate of speed is 60% of Khangʹs. They start out at the same time
\n" ); document.write( "and meet 5 hours later. Find Hectorʹs rate of speed. \n" ); document.write( "

Algebra.Com's Answer #573746 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can think of this as one person standing
\n" ); document.write( "still and the other moving at the sum of their
\n" ); document.write( "speeds
\n" ); document.write( "-------------------
\n" ); document.write( "Let $\"+s+\"$ = Khang's speed in mi/hr
\n" ); document.write( " $\"+.6s+\"$ = Hector's speed in mi/hr
\n" ); document.write( "---------------------------------
\n" ); document.write( " $\"+88+=+%28+s+%2B+.6s+%29%2A5+\"$
\n" ); document.write( " $\"+88+=+1.6s%2A5+\"$
\n" ); document.write( " $\"+8s+=+88+\"$
\n" ); document.write( " $\"+s+=+11+\"$
\n" ); document.write( " $\"+.6s+=+6.6+\"$
\n" ); document.write( "Hector's speed is 6.6 mi/hr
\n" ); document.write( "---------------------------
\n" ); document.write( "check:
\n" ); document.write( "Khang's equation:
\n" ); document.write( "(1) $\"+d%5B1%5D+=+11%2A5+\"$
\n" ); document.write( "(1) $\"+d%5B1%5D+=+55+\"$ mi
\n" ); document.write( "---------------------
\n" ); document.write( "Hector's equation:
\n" ); document.write( "(2) $\"+d%5B2%5D+=+6.6%2A5+\"$
\n" ); document.write( "(2) $\"+d%5B2%5D+=+33+\"$ mi
\n" ); document.write( "---------------------
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+55+%2B+33+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+88+\"$
\n" ); document.write( "OK \n" ); document.write( "

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