document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941191>Question 941191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a quadratic equation such that the sum of its roots is 6 and the product of its roots is -27.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573727 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write a quadratic equation such that the sum of its roots is 6 and the product of its roots is -27. <BR>\n" );
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document.write( "Since the roots are [-b+sqrt(b^2-4ac)]/2a and [-b-sqrt(b^2-4ac)]/(2a)<BR>\n" );
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document.write( "Sum of the roots is 2[-b/(2a)] = -b/a<BR>\n" );
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document.write( "Product is (b^2-(b^2-4ac)]/(4a^2) = 4ac/4a^2 = c/a<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = x^2 - (sum of roots)x + (product of roots)<BR>\n" );
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document.write( "y = x^2 -6x -27<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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