document.write( "Question 941171: Please help,
\n" ); document.write( "36g of an alloy of copper and zinc contains 45% copper. How much pure copper do you need to add in order to get a 60% copper alloy?
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Algebra.Com's Answer #573706 by ankor@dixie-net.com(22740)\"\" \"About 
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36g of an alloy of copper and zinc contains 45% copper.
\n" ); document.write( " How much pure copper do you need to add in order to get a 60% copper alloy?
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\n" ); document.write( "let c = amt of pure copper required
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\n" ); document.write( "write an equation using the decimal equiv of the per cent
\n" ); document.write( "c + .45(36) = .60(c + 36)
\n" ); document.write( "c + 16.2 = .60c + 21.6
\n" ); document.write( "c - .60c = 21.6 - 16.2
\n" ); document.write( ".40c = 5.4
\n" ); document.write( "c = 5.4/.4
\n" ); document.write( "c = 13.5 grams of pure copper required
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\n" ); document.write( "You can confirm this for yourself, replace c with 13.5 in the original equation
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