document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941139>Question 941139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 46 ft. The width is 3ft less than twice the length. Find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573699 by </B><A HREF=/tutors/aboutme.mpl?userid=laoman><B>laoman(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=laoman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=laoman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length be l and width be w<BR>\n" );
document.write( "From first statement, perimeter = 2(l+w)\r<BR>\n" );
document.write( "\n" );
document.write( "2l+2w = 46<BR>\n" );
document.write( "w = 2*l - 3\r<BR>\n" );
document.write( "\n" );
document.write( "solving the simultaneous eqns<BR>\n" );
document.write( "2l+2w = 46<BR>\n" );
document.write( "2l-w = 3\r<BR>\n" );
document.write( "\n" );
document.write( "<TABLE  BORDER=1>\n" );
document.write( "\n" );
document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++2%5Cl+%2B+2%5Cw+=+46%2C%0D%0A++++2%5Cl+%2B+-1%5Cw+=+3+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++2%5Cl+%2B+2%5Cw+=+46%2C%0D%0A++++2%5Cl+%2B+-1%5Cw+=+3+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving 2*w to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Al+=+46+-+2%2Aw ALIGN=MIDDLE  ALT=\"2%2Al+=+46+-+2%2Aw\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+46%2F2+-+2%2Aw%2F2 ALIGN=MIDDLE  ALT=\"l+=+46%2F2+-+2%2Aw%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%2846%2F2+-+2%2Aw%2F2%29+%2B+-1%5Cw+=+3 ALIGN=MIDDLE  ALT=\"2%2A%2846%2F2+-+2%2Aw%2F2%29+%2B+-1%5Cw+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that w=14.3333333333333. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+46%2F2+-+2%2Aw%2F2 ALIGN=MIDDLE  ALT=\"l+=+46%2F2+-+2%2Aw%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, l=8.6666666666667.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+l=8.6666666666667%2C+w=14.3333333333333+%29 ALIGN=MIDDLE  ALT=\"system%28+l=8.6666666666667%2C+w=14.3333333333333+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE><BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "length = 8.67 ft<BR>\n" );
document.write( "width = 14.33 ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );