document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=941110>Question 941110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ONE number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 405, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573686 by </B><A HREF=/tutors/aboutme.mpl?userid=laoman><B>laoman(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=laoman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=laoman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the ONE no. be y, the first no. be x and the third no. z<BR>\n" );
document.write( "From the statement<BR>\n" );
document.write( "y = 3 * x ----eqn1<BR>\n" );
document.write( "z = x + 100 -----eqn 2<BR>\n" );
document.write( "x + y + z = 405 -----eqn3\r<BR>\n" );
document.write( "\n" );
document.write( "let's rearrange the eqns and sole the 3 simultaneous eqns.<BR>\n" );
document.write( "3*x - y = 0<BR>\n" );
document.write( "x - z = -100<BR>\n" );
document.write( "x+y+z = 405\r<BR>\n" );
document.write( "\n" );
document.write( "all the best<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );