document.write( "Question 941031: find the consecutive even integers such that four times the first minus the twice the third is equal to the second.
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Algebra.Com's Answer #573649 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the 3 consecutive even integers be:
\n" ); document.write( " $\"+n+\"$ , $\"+n%2B2+\"$ , and $\"+n%2B4+\"$
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\n" ); document.write( " $\"+4n+-+2%2A%28+n+%2B+4+%29+=+n+%2B+2+\"$
\n" ); document.write( " $\"+4n+-+2n+-+8+=+n+%2B+2+\"$
\n" ); document.write( " $\"+2n+-+8+=+n+%2B+2+\"$
\n" ); document.write( " $\"+n+=+10+\"$
\n" ); document.write( " $\"+n%2B2+=+12+\"$
\n" ); document.write( " $\"+n%2B4+=+14+\"$
\n" ); document.write( "the 3 consecutive even integers are 10, 12, and 14
\n" ); document.write( "check:
\n" ); document.write( " $\"+4n+-+2%2A%28+n+%2B+4+%29+=+n+%2B+2+\"$
\n" ); document.write( " $\"+4%2A10+-+2%2A14+=+12+\"$
\n" ); document.write( " $\"+40+-+28+=+12+\"$
\n" ); document.write( " $\"+12+=+12+\"$
\n" ); document.write( "OK \n" ); document.write( "

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