document.write( "Question 941053: Leah leaves work at 17:54, halfway home she meets her daughter who left home at 17:46. Knowing that Leah walks 1.5x faster than her daughter and that they are travelling in a straight line, at what time do they meet? \n" ); document.write( "
Algebra.Com's Answer #573600 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Find Leah's head start: \n" ); document.write( "17:54 minus 17:46 = 8 min \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "Start a stop watch when daughter leaves \n" ); document.write( "add their speeds to find when they meet \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "They meet at 17:46 + d/(2.5s) - 4.8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |