document.write( "Question 940969: the hypotenuse of a right triangle is 65 cm. one side is 10 cm shorter than twice the other side. find the lengths of the two sides \n" ); document.write( "
Algebra.Com's Answer #573536 by nerdybill(7384)\"\" \"About 
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the hypotenuse of a right triangle is 65 cm. one side is 10 cm shorter than twice the other side. find the lengths of the two sides
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\n" ); document.write( "Let x = side
\n" ); document.write( "then from \"one side is 10 cm shorter than twice the other side\" we have
\n" ); document.write( "2x-10 = second side
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\n" ); document.write( "apply Pythagorean theorem:
\n" ); document.write( "x^2 + (2x-10)^2 = 65^2
\n" ); document.write( "x^2 + (2x-10)(2x-10) = 4225
\n" ); document.write( "x^2 + 4x^2-20x-20x+100 = 4225
\n" ); document.write( "x^2 + 4x^2-40x+100 = 4225
\n" ); document.write( "5x^2-40x+100 = 4225
\n" ); document.write( "x^2-8x+20 = 845
\n" ); document.write( "x^2-8x-825 = 0
\n" ); document.write( "factoring the left:
\n" ); document.write( "(x+25)(x-33) = 0
\n" ); document.write( "x = {-25, 33}
\n" ); document.write( "throw out the negative leaving:
\n" ); document.write( "x = 33 cm (one side)
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\n" ); document.write( "second side:
\n" ); document.write( "2x-10 = 2(33)-10 = 66-10 = 56 cm
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\n" ); document.write( "answer: 33 cm and 56 cm
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