document.write( "Question 940963: The sum of the ages of Diego and Marissa is 96 years. 12 years ago, Diego's age was 3 times Marissa's age. How old is Diego now?
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Algebra.Com's Answer #573532 by algebrahouse.com(1659)\"\" \"About 
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x = Marissa's age now
\n" ); document.write( "96 - x = Diego's age now {the sum of their ages is 96}\r
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\n" ); document.write( "\n" ); document.write( "x - 12 = Marissa's age 12 years ago {subtracted 12 from current age}
\n" ); document.write( "84 - x = Diego's age 12 years ago {subtracted 12 from current age}\r
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\n" ); document.write( "\n" ); document.write( "84 - x = 3(x - 12) {twelve years ago, Diego was three times Marissa}
\n" ); document.write( "84 - x = 3x - 36 {used distributive property}
\n" ); document.write( "4x = 120 {added x and added 36 to each side}
\n" ); document.write( "x = 30 {divided each side by 4}
\n" ); document.write( "96 - x = 66 {substituted 30, in for x, into 96 - x}\r
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\n" ); document.write( "\n" ); document.write( "Marissa is 30
\n" ); document.write( "Diego is 66
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