document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940950>Question 940950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Agbuya can mow a lawn in 3hours. His sons, Michael and Arnel can each do the job in 2hours. If the father and his sons work together. How long will it take them to mow a lawn? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573526 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=Mr.A's rate=1 yard/3 hr=1/3 yard per hour<BR>\n" );
document.write( "S1=Son 1 rate=1 yard/2 hr=1/2 yard per hour<BR>\n" );
document.write( "S2=Son 2 rate=1 yard/2 hr=1/2 yard per hour<BR>\n" );
document.write( "Together=A+S1+S2=1/3 yard/hr+1/2 yard/hr+1/2 yard/hr=1 1/3 yards/hour=4/3 yards/hr<BR>\n" );
document.write( "time=lawns/rate=1 yard/(4/3 yards/hr)=.75 hours<BR>\n" );
document.write( "So it takes all three 3/4 hours or 45 minutes to mow one lawn </SPAN>\n" );
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