document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940885>Question 940885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 171 minus the first of the three consecutive integers is equivalent to the sum of the second and third.  What are your integers?\r<BR>\n" );
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document.write( "I've tried several ways to work this problem but when I plug in the x, it doesn't make sense </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573486 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The consecutive integers: x, (x+1), (x+2)<BR>\n" );
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document.write( "171 minus the first of the three consecutive integers is equivalent to the sum of the second and third.<BR>\n" );
document.write( "171 - x  = (x+1) + (x+2)<BR>\n" );
document.write( "171 - x = 2x + 3<BR>\n" );
document.write( "171 = 2x + x + 3<BR>\n" );
document.write( "171 - 3 = 3x<BR>\n" );
document.write( "168 = 3x<BR>\n" );
document.write( "x = 168/3<BR>\n" );
document.write( "x = 56<BR>\n" );
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document.write( "Try this\r<BR>\n" );
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document.write( " What are your integers?  </SPAN>\n" );
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