document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940870>Question 940870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number exceeds another number by 6. Write these two numbers in terms of x. When twice the larger number is added to three times the smaller number, the result is 32. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573481 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number = x the other X+6<BR>\n" );
document.write( "When twice the larger 2(x+6) is added to three times the smaller (3x)the result is 32. So 2(x+6)+3x=32<BR>\n" );
document.write( "2x+12+3x=32 Multiply out the 2<BR>\n" );
document.write( "5x+12=32 Combine<BR>\n" );
document.write( "5x+12-12=32-12 Subtract 12 from both sides<BR>\n" );
document.write( "5x=20<BR>\n" );
document.write( "5x/5=20/5  Divide both sides by 5<BR>\n" );
document.write( "x=4 ANSWER One number is 4, the other is 4+6=10 <BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "Twice the larger added to 3 x the smaller =32<BR>\n" );
document.write( "2(10)+3(4)=32<BR>\n" );
document.write( "20+12=32<BR>\n" );
document.write( "32=32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );