document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79986>Question 79986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 46 in., find the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57344 by </B><A HREF=/tutors/aboutme.mpl?userid=vertciel><B>vertciel(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vertciel><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello there,\r<BR>\n" );
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document.write( "Perimeter of square (a rectangle is a square BTW) = sum of all sides\r<BR>\n" );
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document.write( "Let w be width.\r<BR>\n" );
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document.write( "So width = w and length = 2 + w since length is 2 inches longer than w.\r<BR>\n" );
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document.write( "Perimeter of square = w + (2 + w) + w + (2 + w)  <--- There are 2 lengths and 2 widths in a square.\r<BR>\n" );
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document.write( "4w + 4 = 46\r<BR>\n" );
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document.write( "Find w and that's your width. Length is 2 + w so just add 2 to width and you have your answer in inches.  \r<BR>\n" );
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