document.write( "Question 940824: Please help me solve the following problem \"The area of a certain rectangle is 288yds^2. the perimeter is 68 yd. If you double he length and width, what will be the area and the preimeter of the new rectangle?\r
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Algebra.Com's Answer #573435 by lwsshak3(11628)\"\" \"About 
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\"The area of a certain rectangle is 288yds^2. the perimeter is 68 yd. If you double he length and width, what will be the area and the preimeter of the new rectangle?
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\n" ); document.write( "Area varies as the square of the increase/decrease in length and width
\n" ); document.write( "If you double the length and width, the area increases by 4 times=4*288=1152 sq yds
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\n" ); document.write( "Perimeter varies directly as the increase/decrease in length and width
\n" ); document.write( "If you double the length and width, the perimeter increases by 2 times=2*68=136 yds
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