document.write( "Question 940785: Cal and Dan are on opposite ends of the same bike path, 39.15 miles apart. They are going to ride their bikes toward each other until they meet. Dan starts pedaling 1.5 hours before Cal. Cal rides 1.8 mph faster than Dan. If they meet 3 hours after Cal starts riding, find the speed of each biker. \n" ); document.write( "

Algebra.Com's Answer #573433 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Cal and Dan are on opposite ends of the same bike path, 39.15 miles apart. They are going to ride their bikes toward each other until they meet. Dan starts pedaling 1.5 hours before Cal. Cal rides 1.8 mph faster than Dan. If they meet 3 hours after Cal starts riding, find the speed of each biker.
\n" ); document.write( "***
\n" ); document.write( "let x=Dan's bike speed
\n" ); document.write( "x+1.8=Cal's bike speed
\n" ); document.write( "travel time*speed=distance..
\n" ); document.write( "..
\n" ); document.write( " $\"%283%2B1.5%29%2Ax%2B3%2A%28x%2B1.8%29=39.15\"$
\n" ); document.write( "4.5x+3x+5.4=39.15
\n" ); document.write( "7.5x=33.75
\n" ); document.write( "x=4.5
\n" ); document.write( "x+1.8=6.3
\n" ); document.write( "Dan's bike speed=4.5 mph
\n" ); document.write( "Cal's bike speed=6.3 mph \n" ); document.write( "

\n" );