document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940765>Question 940765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of one angle is one-third the measure of the other. Find the measures of both angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573389 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of one angle is one-third the measure of the other. Find the measures of both angles.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 180<BR>\n" );
document.write( "x = (1/3)y<BR>\n" );
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document.write( "Subtritute for \"x\" and solve for \"y\"::<BR>\n" );
document.write( "(1/3)y + y = 180<BR>\n" );
document.write( "(4/3)y = 180<BR>\n" );
document.write( "(1/3)y = 45<BR>\n" );
document.write( "y = 135 degrees<BR>\n" );
document.write( "x = 180-135 = 45 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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