document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940743>Question 940743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equations in logarithmic form \r<BR>\n" );
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document.write( "512 = 8 to the 3rd power\r<BR>\n" );
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document.write( "16= (1/4) to the -2nd power\r<BR>\n" );
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document.write( "a = bc but the c is squared  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573368 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write the equations in logarithmic form <BR>\n" );
document.write( "512 = 8 to the 3rd power<BR>\n" );
document.write( "exponent = log = 3<BR>\n" );
document.write( "base = 8<BR>\n" );
document.write( "result = 512<BR>\n" );
document.write( "Ans: log8(512) = 3<BR>\n" );
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document.write( "16= (1/4) to the -2nd power<BR>\n" );
document.write( "log(1/4)16 = -2<BR>\n" );
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document.write( "a = bc but the c is squared <BR>\n" );
document.write( "c^2 = a/b<BR>\n" );
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document.write( "logc(a/b) = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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