document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940677>Question 940677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the larger of the two numbers is divided by the smaller,the quotient and the reminder are 2 each.If 5 times the smaller number is divided by the larger,the quotient and the reminder are still 2 each.Find the two numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573358 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the larger number be x.<BR>\n" );
document.write( "let the smaller number be y.\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "larger number divided by smaller number = 2 + remainder of 2 becomes:\r<BR>\n" );
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document.write( "x/y = 2 + 2/y\r<BR>\n" );
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document.write( "5 times smaller number divided by larger number= 2 + remainder of 2 becomes:\r<BR>\n" );
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document.write( "5y/x = 2 + 2/x\r<BR>\n" );
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document.write( "solve for x in the equation of x/y = 2 + 2/y to get:\r<BR>\n" );
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document.write( "x = 2y + 2\r<BR>\n" );
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document.write( "replace x with 2y + 2 in the equation of 5y/x = 2 + 2/x to get:\r<BR>\n" );
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document.write( "5y/(2y + 2) = 2 / (2y + 2)\r<BR>\n" );
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document.write( "solve for y in this equation to get:\r<BR>\n" );
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document.write( "y = 6\r<BR>\n" );
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document.write( "replace y with 6 in the equation of x/y = 2 + 2/y to get:\r<BR>\n" );
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document.write( "x = 14\r<BR>\n" );
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document.write( "14/6 = 2 + remainder of 2.\r<BR>\n" );
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document.write( "5 * 6 = 30 / 14 = 2 + remainder of 2.\r<BR>\n" );
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document.write( "the solution is correct.\r<BR>\n" );
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