document.write( "Question 940711: Vic is now 24 years older than his brother. in six years, he will be twice as older as his brother's age. What are their present ages \n" ); document.write( "
Algebra.Com's Answer #573324 by macston(5194)![]() ![]() You can put this solution on YOUR website! V=Vic's age; B= brother's age \n" ); document.write( "V=B+24 years; V+6years=2(B+6years) \n" ); document.write( "(B+24 years)+6 years=2(B+6 years) \n" ); document.write( "B+30 years=2B+12 years Subtract 12 from both sides \n" ); document.write( "B+30 years-12 years=2B+12 years-12 years \n" ); document.write( "B+18 years=2B Subtract B from both sides \n" ); document.write( "B+18 years-B=2B-B \n" ); document.write( "18=B ANSWER 1 Brother's age=18 years \n" ); document.write( "V=B+24 \n" ); document.write( "V=18+24=42 ANSWER 2 Vic's age=42 years \n" ); document.write( "CHECK: \n" ); document.write( "In six years he will be twice as old as his brother. \n" ); document.write( "V+6= 2(B+6) \n" ); document.write( "42+6=2(28+6) \n" ); document.write( "48=2(24) \n" ); document.write( "48=48 \n" ); document.write( " |