document.write( "Question 940709: In still water, Mo and Sally can paddle a canoe at 12 mph. It takes them a total of 6 hours to paddle 32 miles up a river and then return the same distance to their starting point. What is the rate of the current?
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Algebra.Com's Answer #573319 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+12+\" mi/hr is their speed in still water
\n" ); document.write( "Let \"+c+\" = the speed of the current in mi/hr
\n" ); document.write( "\"+12+%2B+c+\" = their speed in mi/hr going downriver
\n" ); document.write( "\"+12+-+c+\" = their speed in mi/hr going upriver
\n" ); document.write( "Let \"+t+\" = their time in hours to go upriver
\n" ); document.write( "\"+6+-+t+\" = their time in hours to go downriver
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\n" ); document.write( "Equation for going upriver:
\n" ); document.write( "(1) \"+32+=+%28+12+-+c+%29%2At+\"
\n" ); document.write( "Equation for going downriver:
\n" ); document.write( "(2) \"+32+=+%28+12+%2B+c+%29%2A%28+6+-+t+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(1) \"+32+=+12t+-+c%2At+\"
\n" ); document.write( "(1) \"+c%2At+=+12t+-+32+\"
\n" ); document.write( "(1) \"+c+=+12+-+32%2Ft+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+32+=+72+%2B+6c+-+12t+-+c%2At+\"
\n" ); document.write( "(2) \"+40+=+12t+-+6c+%2B+c%2At+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+40+=+12t+-+6%2A%28+12+-+32%2Ft+%29+%2B+%28+12+-+32%2Ft+%29%2At+\"
\n" ); document.write( "(2) \"+40+=+12t+-+72+%2B+192%2Ft+%2B+12t+-+32+\"
\n" ); document.write( "(2) \"+144+=+192%2Ft+%2B+24t+\"
\n" ); document.write( "(2) \"+18+=+24%2Ft+%2B+3t+\"
\n" ); document.write( "(2) \"+18t+=+24+%2B+3t%5E2+\"
\n" ); document.write( "(2) \"+3t%5E2+-+18t+%2B+24+=+0+\"
\n" ); document.write( "Use the quadratic formula
\n" ); document.write( "\"+t+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+3+\"
\n" ); document.write( "\"+b+=+-18+\"
\n" ); document.write( "\"+c+=+24+\"
\n" ); document.write( "\"+t+=+%28+-%28-18%29+%2B-+sqrt%28+%28-18%29%5E2+-+4%2A3%2A24+%29%29+%2F+%282%2A3%29+\"
\n" ); document.write( "\"+t+=+%28+18+%2B-+sqrt%28+324+-+288+%29%29+%2F+6+\"
\n" ); document.write( "\"+t+=+%28+18+%2B-+sqrt%28+36+%29%29+%2F+6+\"
\n" ); document.write( "\"+t+=+%28+18+%2B+6+%29+%2F+6+\"
\n" ); document.write( "\"+t+=+24%2F6+\"
\n" ); document.write( "\"+t+=+4+\" hrs ( I picked the right square root because
\n" ); document.write( "the trip upriver should take longer than downriver )
\n" ); document.write( "\"+6+-+t+=+6+-+4+\"
\n" ); document.write( "\"+6+-+t+=+2+\" hrs
\n" ); document.write( "-------------------
\n" ); document.write( "(1) \"+32+=+%28+12+-+c+%29%2At+\"
\n" ); document.write( "(1) \"+32+=+%28+12+-+c+%29%2A4+\"
\n" ); document.write( "(1) \"+8+=+12+-+c+\"
\n" ); document.write( "(1) \"+c+=+4+\"
\n" ); document.write( "The rate of the current is 4 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "(2) \"+32+=+%28+12+%2B+c+%29%2A%28+6+-+t+%29+\"
\n" ); document.write( "(2) \"+32+=+%28+12+%2B+4+%29%2A%28+6+-+4+%29+\"
\n" ); document.write( "(2) \"+32+=+16%2A2+\"
\n" ); document.write( "(2) \"+32+=+32+\"
\n" ); document.write( "OK\r
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