document.write( "Question 940662: The sum of 7 times Paul's age and 4 times Kent's age is 111. Kent is 1 year less than 4 times as old as Paul is. Find each's age. \n" ); document.write( "
Algebra.Com's Answer #573294 by macston(5194)\"\" \"About 
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7P + 4K = 111 years (sum of 7 Paul and 4 Kent= 111)
\n" ); document.write( "4P - 1 = K (Kent's age is 4 times Paul's -1)
\n" ); document.write( "Substitute for K in first equation and solve for P:
\n" ); document.write( "7P + 4(4P-1)=111 years
\n" ); document.write( "7P + 16P -4=111 years
\n" ); document.write( "23P-4=111 years
\n" ); document.write( "23P=115 years
\n" ); document.write( "P=5 years ANSWER 1 Paul's Age
\n" ); document.write( "Find Kent's age:
\n" ); document.write( "K=4P-1
\n" ); document.write( "K=4(5 years)-1
\n" ); document.write( "K=20 years-1=19 years ANSWER 2 Kent's Age
\n" ); document.write( "CHECK
\n" ); document.write( " Sum of 7 times Paul's age(7*5) and 4 times Kent's age (4*19) is 111
\n" ); document.write( "(7*5)+(4*19)=111
\n" ); document.write( "35+76=111
\n" ); document.write( "111=111\r
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