document.write( "Question 940619: One car travels at 30 km/h faster then another. While one travels 300 km the other travels 450 km. find their speed \n" ); document.write( "

Algebra.Com's Answer #573256 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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One car travels at 30 km/h faster then another.
\n" ); document.write( " While one travels 300 km the other travels 450 km.
\n" ); document.write( " find their speed
\n" ); document.write( ":
\n" ); document.write( "let s = the slow car's speed
\n" ); document.write( "then
\n" ); document.write( "(s+30) = the faster car's speed
\n" ); document.write( ":
\n" ); document.write( "Speed and distance are directly related, write a proportion equation
\n" ); document.write( " $\"s%2F%28%28s%2B30%29%29\"$ = $\"300%2F450\"$
\n" ); document.write( "cross multiply
\n" ); document.write( "450s = 300(s+30)
\n" ); document.write( "450s = 300s + 9000
\n" ); document.write( "450s - 300s = 9000
\n" ); document.write( "150s = 9000
\n" ); document.write( "s = 9000/150
\n" ); document.write( "s = 60 km/hr is the slow car speed
\n" ); document.write( "and obviously,
\n" ); document.write( "90 km/hr is the fast car speed
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "You can confirm this by finding the time of each, should be equal
\n" ); document.write( "300/60 = 5 hrs
\n" ); document.write( "450/90 = 5 \n" ); document.write( "

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