document.write( "Question 940286: two roads crew working together repaired 1 mile of the road in four hours. working separately one of the crews takes about six hours to repair a similar road. how long would it take the other crew working alone to repair a similar Road? \n" ); document.write( "
Algebra.Com's Answer #573233 by ankor@dixie-net.com(22740)\"\" \"About 
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two roads crew working together repaired 1 mile of the road in four hours.
\n" ); document.write( " working separately one of the crews takes about six hours to repair a similar road.
\n" ); document.write( " how long would it take the other crew working alone to repair a similar Road?
\n" ); document.write( ":
\n" ); document.write( "let t = time required by the \"other crew\" to do the job
\n" ); document.write( "let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "\"4%2F6\" + \"4%2Ft\" = 1
\n" ); document.write( "Each crew does a fraction of the job, the two fractions add up to 1
\n" ); document.write( "multiply equation by 6t, cancel the denominators and you have:
\n" ); document.write( "4t + 6(4) = 6t
\n" ); document.write( "24 = 6t - 4t
\n" ); document.write( "24 = 2t
\n" ); document.write( "t = 24/2
\n" ); document.write( "t = 12 hrs for the other crew to do the job
\n" ); document.write( ":
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\n" ); document.write( "Check this
\n" ); document.write( "\"4%2F6\" + \"4%2F12\" = 1
\n" ); document.write( "reduce fractions
\n" ); document.write( "\"2%2F3\" + \"1%2F3\" = 1
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