document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79911>Question 79911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (64)^2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57323 by </B><A HREF=/tutors/aboutme.mpl?userid=tutor_paul><B>tutor_paul(519)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutor_paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutor_paul><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Raising something to the 2/3 power means square it and take the cube root of it (the order in which you do these does not matter). I would first take the cube root of 64, since I now that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x4x4=64 ALIGN=MIDDLE  ALT=\"4x4x4=64\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So now I am left with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E2 ALIGN=MIDDLE  ALT=\"4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. You should be able to figure that out.<BR>\n" );
document.write( "Good Luck,<BR>\n" );
document.write( "tutor_paul@yahoo.com </SPAN>\n" );
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