document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=940621>Question 940621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 48 m. If the width were doubled and the length were increased by 24 m, the perimeter would be 112 m. What are the length and width of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #573228 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=573228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 48 m. If the width were doubled and the length were increased by 24 m, the perimeter would be 112 m. What are the length and width of the rectangle?<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "Original DATA<BR>\n" );
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document.write( "48 = 2(L + W)<BR>\n" );
document.write( "L+W = 24 meters<BR>\n" );
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document.write( "Modified DATA:<BR>\n" );
document.write( "112 = 2(L+24 + 2W)<BR>\n" );
document.write( "56 = L + 2W + 24<BR>\n" );
document.write( "L + 2W = 32<BR>\n" );
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document.write( "Solve the System::<BR>\n" );
document.write( "L + W = 24<BR>\n" );
document.write( "L + 2W = 32<BR>\n" );
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document.write( "Subtract and solve for \"W:<BR>\n" );
document.write( "W = 8 (original width)<BR>\n" );
document.write( "L = 24-8 = 16 (original length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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