document.write( "Question 940543: Roberto needs a solution that is 30% silver nitrate. He has 12 ounces of a 25% silver nitrate solution. How many ounces of a 40% silver nitrate solution should he add to make a solution that is 30% silver nitrate? \n" ); document.write( "
Algebra.Com's Answer #573205 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = ounces of 40% solution to be added
\n" ); document.write( "\"+.4x+\" = ounces of silver nitrate in 40% solution
\n" ); document.write( "\"+.25%2A12+=+3+\" = ounces of silver nitrate in 25% silver nitrate solution
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+%28+3+%2B+.4x+%29+%2F+%28+12+%2B+x+%29+=+.3+\"
\n" ); document.write( "\"+3+%2B+.4x+=+.3%2A%28+12+%2B+x+%29+\"
\n" ); document.write( "\"+3+%2B+.4x+=+3.6+%2B+.3x+\"
\n" ); document.write( "\"+.1x+=+.6+\"
\n" ); document.write( "\"+x+=+6+\"
\n" ); document.write( "6 ounces of the 40% solution should be added
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+3+%2B+.4x+%29+%2F+%28+12+%2B+x+%29+=+.3+\"
\n" ); document.write( "\"+%28+3+%2B+.4%2A6+%29+%2F+%28+12+%2B+6+%29+=+.3+\"
\n" ); document.write( "\"+5.4+%2F+18+=+.3+\"
\n" ); document.write( "\"+5.4+=+5.4+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );